3.1.59 \(\int \frac {(a+b x)^2}{x^4} \, dx\) [59]

Optimal. Leaf size=17 \[ -\frac {(a+b x)^3}{3 a x^3} \]

[Out]

-1/3*(b*x+a)^3/x^3/a

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Rubi [A]
time = 0.00, antiderivative size = 17, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {37} \begin {gather*} -\frac {(a+b x)^3}{3 a x^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^2/x^4,x]

[Out]

-1/3*(a + b*x)^3/(a*x^3)

Rule 37

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n +
1)/((b*c - a*d)*(m + 1))), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && EqQ[m + n + 2, 0] && NeQ
[m, -1]

Rubi steps

\begin {align*} \int \frac {(a+b x)^2}{x^4} \, dx &=-\frac {(a+b x)^3}{3 a x^3}\\ \end {align*}

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Mathematica [A]
time = 0.00, size = 26, normalized size = 1.53 \begin {gather*} -\frac {a^2}{3 x^3}-\frac {a b}{x^2}-\frac {b^2}{x} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^2/x^4,x]

[Out]

-1/3*a^2/x^3 - (a*b)/x^2 - b^2/x

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Maple [A]
time = 0.07, size = 25, normalized size = 1.47

method	result	size
gosper	\(-\frac {3 x^{2} b^{2}+3 a b x +a^{2}}{3 x^{3}}\)	\(23\)
norman	\(\frac {-x^{2} b^{2}-a b x -\frac {1}{3} a^{2}}{x^{3}}\)	\(24\)
risch	\(\frac {-x^{2} b^{2}-a b x -\frac {1}{3} a^{2}}{x^{3}}\)	\(24\)
default	\(-\frac {b^{2}}{x}-\frac {a^{2}}{3 x^{3}}-\frac {a b}{x^{2}}\)	\(25\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^2/x^4,x,method=_RETURNVERBOSE)

[Out]

-b^2/x-1/3*a^2/x^3-a*b/x^2

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Maxima [A]
time = 0.27, size = 22, normalized size = 1.29 \begin {gather*} -\frac {3 \, b^{2} x^{2} + 3 \, a b x + a^{2}}{3 \, x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/x^4,x, algorithm="maxima")

[Out]

-1/3*(3*b^2*x^2 + 3*a*b*x + a^2)/x^3

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Fricas [A]
time = 1.10, size = 22, normalized size = 1.29 \begin {gather*} -\frac {3 \, b^{2} x^{2} + 3 \, a b x + a^{2}}{3 \, x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/x^4,x, algorithm="fricas")

[Out]

-1/3*(3*b^2*x^2 + 3*a*b*x + a^2)/x^3

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Sympy [A]
time = 0.05, size = 24, normalized size = 1.41 \begin {gather*} \frac {- a^{2} - 3 a b x - 3 b^{2} x^{2}}{3 x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**2/x**4,x)

[Out]

(-a**2 - 3*a*b*x - 3*b**2*x**2)/(3*x**3)

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Giac [A]
time = 1.12, size = 22, normalized size = 1.29 \begin {gather*} -\frac {3 \, b^{2} x^{2} + 3 \, a b x + a^{2}}{3 \, x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^2/x^4,x, algorithm="giac")

[Out]

-1/3*(3*b^2*x^2 + 3*a*b*x + a^2)/x^3

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Mupad [B]
time = 0.04, size = 22, normalized size = 1.29 \begin {gather*} -\frac {\frac {a^2}{3}+a\,b\,x+b^2\,x^2}{x^3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x)^2/x^4,x)

[Out]

-(a^2/3 + b^2*x^2 + a*b*x)/x^3

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